|
|
联系方式 Contact us |
常州市鼎智悦凯机电有限公司 手机:13775090797 邮箱:sales@dzykmotor.com 地址:常州市武进区人民中路151号
|
|
|
|
|
您当前的位置:首页 - 新闻中心 |
|
选型计算 |
发布者:admin 发布时间:2017-07-19 15:13:31 阅读:342次 |
|
|
|
|
|
丝杠水平运动选型计算表格 |
|
|
|
|
|
|
|
|
机械结构参数: |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
速度: |
|
Vl= |
10 |
m/min |
* |
其他常数 |
|
|
|
|
|
|
|
|
|
滑动部分质量 |
M= |
8 |
kg |
* |
|
G= |
9.8 |
m/s |
|
|
|
|
|
|
丝杠长度 |
|
LB= |
0.6 |
m |
* |
|
pi= |
3.1416 |
|
|
|
|
|
|
|
丝杠直径 |
|
DB= |
0.04 |
m |
* |
丝杠密度 |
ρ= |
7900 |
kg/m3 |
|
|
|
|
|
|
丝杠导程 |
|
PB= |
0.019 |
m |
* |
Bitmap Bitmap
|
|
|
|
|
|
|
|
|
连轴器质量 |
|
MC |
2 |
kg |
* |
|
|
|
|
|
|
|
|
连轴器直径 |
|
DC |
0.05 |
m |
* |
|
|
|
|
|
|
|
|
摩擦系数 |
|
μ= |
0.1 |
|
* |
|
|
|
|
|
|
|
|
移动距离 |
|
L= |
0.3 |
m |
|
|
|
|
|
|
|
|
|
机械效率 |
|
η= |
0.9 |
|
* |
|
|
|
|
|
|
|
|
|
|
定位时间 |
|
t= |
1 |
s |
* |
|
|
|
|
|
|
|
|
|
|
加减速时间比 |
A= |
25% |
|
* |
|
|
|
|
|
|
|
|
|
|
外力 |
|
Bitmap Bitmap Pict
|
0 |
N |
|
|
|
|
|
|
|
|
|
移动方向与水平轴夹角 |
a = |
0 |
° |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1)速度曲线 |
|
|
|
|
|
|
|
|
|
|
|
|
加速时间 |
|
t0= |
t*A |
|
|
|
|
|
|
|
|
|
|
|
= |
0.25 |
s |
|
|
|
|
|
|
|
2)电机转速 |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
NM = |
Vl/PB |
|
|
|
|
|
|
|
|
|
|
|
= |
526.3157895 |
rpm |
|
|
|
|
|
|
|
3)负荷转矩计算 |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
轴向负载F = |
FA+ |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
= |
7.84 |
N |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
Pict |
|
|
|
|
|
|
|
|
|
|
|
|
|
负载转矩TL = |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
= |
0.02634185 |
Nm |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
4)克服惯量的加速转矩计算(也称做:启动转矩) |
Pict
|
|
|
|
|
|
|
|
|
|
|
|
|
|
直线运动平台与负载惯量 |
JL = |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
= |
7.31536E-05 |
kgm2 |
|
|
|
|
|
|
|
|
|
|
|
|
|
Pict
|
|
|
|
|
|
|
|
|
|
|
|
|
|
滚珠丝杠惯量 |
JB = |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
= |
0.001191295 |
kgm2 |
|
|
|
|
|
|
|
|
|
|
|
|
|
Pict
|
|
|
|
|
|
|
|
|
|
|
|
|
|
连轴器惯量 |
|
JC= |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
= |
0.000625 |
kgm2 |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
总负荷惯量 |
|
JL= |
JL+JB+JC |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
= |
0.001889448 |
kgm2 |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
启动转矩 |
|
TS= |
Pict |
|
安全系数 |
S= |
1 |
|
|
|
|
|
|
|
|
|
= |
0.659063207 |
Nm |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
5)必须转矩 |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
必须转矩 |
|
TM= |
(TL+TS)*S |
|
|
电机惯量 |
JM= |
0.0011 |
kgm2 |
|
|
|
|
|
|
|
|
= |
0.685405056 |
Nm |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
6)电机选择 |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
根据计算,初步确定电机型号,然后输入转子惯量,确认TM |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
7)负荷与电机惯量比 |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
惯量比 |
|
I1= |
1.717680248 |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
8)负荷与减速机惯量比 |
|
|
|
|
|
|
|
|
|
|
|
|
|
当负荷与电机惯量比>5时,考虑采用减速装置,提高惯量匹配 |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
折算后的惯量比 |
I2= |
0.107355015 |
|
|
减速机减速比 |
i= |
4 |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
| |
|
|
|
|
|